7x+y^3+7x^3+6x-3y^3-2x^3+3x

Mathematics

1 answer:

musickatia [10]3 years ago

8 0

Answer:

5x^3 + 16x - 2y^3

Step-by-step explanation:

7x + y^3 + 7x^3 + 6x - 3y^3 - 2x^3 + 3x

group like terms

= 7x^3 - 2x^3 + 7x + 6x + 3x + y^3 - 3y^3

add similar items

= 5x^3 + 7x + 6x + 3x + y^3 - 3y^3

add similar items

= 5x^3 + 16x + y^3 - 3y^3

add similar items

= 5x^3 + 16x - 2y^3

You might be interested in

Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is

olga nikolaevna [1]

The distance between B and B' will be the same as distance between A and A'.

= sqrt ( (5-1)^2 + ( 1 - -2)^2)

= sqrt (16 + 9)

= 5 units answer

6 0

3 years ago

Read 2 more answers

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$