The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
0.25
Step-by-step explanation:
1 divided by 4 = 0.25
If you're trying to solve for y,
5y-4=7
bring over the -4
5y=11
5y/5 = y
11/5 = 2.2
y= 2.2
The question is an illustration of arithmetic operations.
The integer that represents the vertical rise is 76
<em>Upward movements are represented with positive, while downward movements are represented with negative.</em>
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So, the given parameters are:
The vertical rise is:
So, we have:
Hence, the integer that represents the vertical rise is 76
Read more about arithmetic operations at:
brainly.com/question/15385899
Answer:
15 and 5 hours.
Step-by-step explanation:
Call x the time taken by the first chap, and y the second.
Let's divide by 5 and play with the LHS of the first equation a bit:
we know how much x+y is ( first equation!) let's solve.
At this point it's easy to check that 
