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3 years ago

What do the following equations represent -4x-4y=-5 and x-2y=1

Mathematics

1 answer:

Semmy [17]3 years ago

5 0

Answer:

The answer to your question is: D = non of the above

Step-by-step explanation:

Data

-4x - 4y = -5 (I)

x - 2y = 1 (II)

Process

Find the slopes of both lines

(I) -4x - 4y = -5

-4y = 4x + 5

y = 4/-4 x + 5/-4

y = - x + 5/4

(II) x - 2y = 1

- 2y = - x + 1

y = -1/-2 x + 1/-2

y = 1/2 x - 1/2

The slopes are different slope 1 = -1 and slope 2 = 1/2, so there is no relation between the lines.

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What is 800-5x divided by 6.5

MA_775_DIABLO [31]

Answer:10 over 13 x

Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2

to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13

factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)

for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x

solution: 800-10 over 13x so your answer would still be

8 0

3 years ago

If the area of a circle is 121pie square units, what is the diameter

velikii [3]

Since you are given the area, we can solve for radius with this equation:
$A_c = \pi r^2$
$r = \sqrt{ \frac{A_c}{ \pi } } = \sqrt{ \frac{121 \pi }{ \pi } } = \sqrt{121} = 11$

The radius is 11, so the diameter must be 2 times that, which is 22. With the correct units, the answer is 22 units²

4 0

2 years ago

On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her

-BARSIC- [3]

Answer:

14 mph ( average speed during the second part of the trip )

Step-by-step explanation:

Let´s call "x" the average speed during the first part then

t = 5 hours

t = t₁ + t₂ t₁ and t₂ times during part 1 and 2 respectively

l = t*v ( distance is speed by time ) t = l/v

First part

t₁ = 16/x and t₂ = 42 / ( x + 6)

Then

t = 5 = 16/x + 42 /(x + 6)

5 = [ 16 * ( x + 6 ) + 42 * x ] / x* ( x + 6 )

5 *x * ( x + 6 ) = 16*x + 96 + 42 x

5*x² + 30*x - 58*x - 96 = 0

5*x² - 28*x - 96 = 0

We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense

x₁,₂ = [28 ± √ (28)² + 1920 ] / 10

x₁,₂ = ( 28 ± √2704 )/ 10

x₁ = 28 - 52 /10 we dismiss that root

x₂ = 80/10

x₂ = 8 mph average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph

6 0

3 years ago

Carly needed to study for 5/6 of an hour for 9 days. How many hours did she study?

vovikov84 [41]

Answer:

180 hours

Step-by-step explanation:

24 hrs in a day

5/6 of 24 is 20 and multiply it by 9 because there are 9 days

=180

3 0

3 years ago