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3 years ago

The graph shows the relationship between the number of minutes Maria spent jogging on a treadmill and the distance she jogged.

Mathematics

2 answers:

-BARSIC- [3]3 years ago

5 0

Answer: 0.1 mile per minute

Step-by-step explanation:

I’ve just took the quiz and got it right

Option A

Ymorist [56]3 years ago

4 0

Answer:

option A

Step-by-step explanation:

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Find the amount of empty space within a cylinder containing three solid spheres, where each sphere has a radius of 3 cm. (Volume

zimovet [89]

Answer:

Step-by-step explanation:

cylinder's height=3×(diameter of sphere)=3×6=18 cm

radius of cylinder=3 cm

volume of cylinder=π r²h=π(3)²×18=162 π cm³

volume of sphere=4/3 π(3)³=36 π cm³

reqd. empty space=162 π-3×36π=54 πcm³

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4 years ago

M-6=10<br><br> What does m equal?

Sliva [168]

M is 6 more than 10 so it will be 16

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3 years ago

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Find the area and perimeter of trapezium.

neonofarm [45]

Answer:

Perimeter- 26cm

Area- I Don't know sorry. I'll comment if I figure it out

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3 years ago

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Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

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2 years ago

What is 1/2 divided by 4?

Natasha_Volkova [10]

1/2/4=1/2 x 1/4 = 1/8

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3 years ago

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