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miv72 [106K]
3 years ago
5

Subtract the following equation

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

its just a black screeeeen

Step-by-step explanation:


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Noah picked 3 kilograms of cherries. Mai picked half as many cherries as Noah. How many total kilograms of cherries die Mia and
Angelina_Jolie [31]

it would be 4.5 total

6 0
3 years ago
Solve the system of equations using substitution and Elimination
juin [17]
<h2>Greetings!</h2>

Answer:

y = \frac{-18}{7} and x = \frac{50}{7}

Step-by-step explanation:

To solve simultaneous equations, you need to have the number in front of both x's or y's the same. (signs doesn't matter)

To get -x to -10x we simply  need to multiply the first equation by 10:

-x * 10 = -10x

-9y * 10 = -90y

16 * 10 = 160

-10x - 90y = 160

Now we can add the two equations:

-10x + 10x = 0

-90y + 20y = -70y

160 + 20 = 180

-70y = 180

70y = -180

7y = -18

y = \frac{-18}{7}

Now plug \frac{-18}{7} into the second equation:

10x + 20(\frac{-18}{7}) = 20

10x - \frac{360}{7} = 20

Move the \frac{360}{7} over to the other side, making it a positive:

10x = 20 + \frac{360}{7}

10x = \frac{500}{7}

Divide both sides by 10:

x = \frac{50}{7}

So y = \frac{-18}{7} and x = \frac{50}{7}


<h2>Hope this helps!</h2>
5 0
3 years ago
I NEED HELP ASAP!!!! PLEASE ANSWER
dmitriy555 [2]

2nd ones your answer


6 0
3 years ago
Read 2 more answers
Need help..thanks......
Vinvika [58]

Answer: D) Flat area with a large number of plants

The roots of the plants hold in the soil, which prevents/reduces erosion.

The steeper slope means gravity pulls down the soil material faster, since there is less ground in the way to hold it up, so to speak. So flatter areas are less prone to erosion compared to steeper areas.

So that's why overall, flatter areas with lots of plants would have the least erosion.

7 0
3 years ago
G verify that the divergence theorem is true for the vector field f on the region
Alenkasestr [34]
\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1

Converting to spherical coordinates, we have

\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi

On the other hand, we can parameterize the boundary of E by

\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\pi. Now, consider the surface element

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv
=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi

as required.
3 0
3 years ago
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