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baherus [9]
3 years ago
12

Josie is training for a race. The ratio of the number of minutes she runs to the number of miles she runs is 24 to 3. She plans

to run 10 miles. How many minutes will it take her.
Mathematics
2 answers:
Elanso [62]3 years ago
4 0

Answer:

Step-by-step explanation:

if 3 miles = 24 minutes, then 1 mile = 24/3 = 8 minutes

therefore 10 miles = 8 x 10 = 80 minutes

ELEN [110]3 years ago
4 0

Answer:

80

Step-by-step explanation:

The ratio can be simplified and rewritten:

minutes : miles = 24 : 3 = 8 : 1 = 80 : 10

It will take Josie 80 minutes to run 10 miles at her 8 minutes/mile pace.

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3^-2 = 0.111111111 ← Answer
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Kai had 15 yards of kite string. He
n200080 [17]

Answer:

he cut 5 strings to pull it out

3 0
2 years ago
x^2-y=7 and y-5x=-11 The system of equations above has two solutions. The solution in Quadrant 1 is (A,B) and the solution in Qu
dimaraw [331]

By solving the system of equations, we can see that the solutions are:

(A, B) = (4, 9)

(C, D) = (1, -6).

<h3>How to solve the system of equations?</h3>

Here we have the following system of equations:

x^2 - y = 7

y - 5x = -11

If we isolate the variable y in both equations, we get:

y = x^2 - 7

y = -11 + 5x

Now we can equate these two to get:

x^2 - 7 = -11 + 5x

now we have a quadratic equation, this can be rewritten as:

x^2 - 7 + 11 - 5x = 0

x^2 - 5x + 4 = 0

Using the quadratic formula, we will see that the solutions are:

x = \frac{5 \pm \sqrt{(-5)^2 - 4*1*(4)} }{2*1}

Solving that we get:

x = \frac{5 \pm \sqrt{(9} }{2} \\\\x = \frac{5 \pm 3}{2}

So the two solutions for x are:

x = (5 + 3)/2 = 4

x = (5 - 3)/2 = 1

Evaluating the second equation in these x-values we get:

y = -11 + 5*4 = -11 + 20 = 9

y = -11 + 5*1 = -6

Then we have the coordinate pairs: (4, 9) (on the first quadrant) and (1, -6) on the fourth quadrant.

Learn more about systems of equations:

brainly.com/question/13729904

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8 0
1 year ago
please help me :( I need help
slava [35]

Answer:

Step-by-step explanation:

Lines l and m are the parallel lines and 't' is a transversal line,

Therefore, ∠1 ≅ ∠5 [Corresponding angle postulate]

∠5 ≅ ∠7 [Vertical angles theorem]

∠1 ≅ ∠7 [Transitive property]

Therefore, ∠1 ≅ ∠7 [Alternate exterior angles theorem]

4 0
3 years ago
A plastics manufacturer has developed a new type of plastic trash can and proposes to sell them with an unconditional 6-year war
gtnhenbr [62]

Answer:

since -3.73 is less than 1.645, we reject H₀.    

Therefore this indicate that the proposed warranty should be modified

Step-by-step explanation:

Given that the data in the question;

p" = 13/20 = 0.65

Now  the test hypothesis;

H₀ : p = 0.9

Hₐ : p < 0.9

Now lets determine the test statistic;

Z = (p" - p ) / √[p×(1-p)/n]

= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]  

= -0.25 / √[0.9 × 0.1 / 20 ]

= -0.25 / √0.0045

= -0.25 / 0.067

= - 3.73

Now given that a = 0.05,

the critical value is Z(0.05) = 1.645 (form standard normal table)

Now since -3.73 is less than 1.645, we reject H₀.    

Therefore this indicate that the proposed warranty should be modified

3 0
2 years ago
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