Answer: a) 15 b)
Step-by-step explanation:
Let X be the number of days:
a)
For LESSONS:
Jordan does 10 / day ( 10*X)
Marco 5 / day ( 5*X)
Junyi 5 / day ( 5*X)
For TESTS:
Jordan does 5 / day ( 5*X)
Marco 10 / day ( 10*X)
Junyi 8 / day ( 8*X)
for each they need a total of 300
a)
days for the lessons
b)
days for the tests
so they need 15 days to finish both tasks
now if Junyi gets sick we just eliminate his contribution
a)
days for the lessons
b)
days for the tests
so in 20 days they will finish without him
If jordan works 10 hours a day, we just replace him with 10/24
a)
days for the lessons
b)
days for the tests
so at the end to complete both tasks they need 29.58 days
Answer:
use papamath it will give u the anwers
Step-by-step explanation:
Answer:
$11,728
Step-by-step explanation:
Twice a year, for 4 years is 8 times
516×8 = 4128
Yearly for 4 years is 4 times
700×4 = 2800
Every month for 4 years is 48 times
100×48 = 4800
Minimum expenditure:
4128 + 2800 + 4800 = $11,728
First, I would solve the second parenthesis.
(4xy^3)^2
Distribute
(4^2 x^2 y^6)
4 x 4 = 16
Now, combine like terms
3x^2 x 4x^2 = 12x^4
y^2 x y^6 = y^12
So, the answer would be 12x^4 y^12
Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong