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3 years ago

how do you have a reflection in the x axis, if the shape is already partially in the third and second quadrent of the graph

1 answer:

8 0

Its a reflection over an x-axis, whats "positive" goes "negative" and whats "negative" goes "positive" with respect to y.

If a shape $S$ is a subset (made of $P_2\cup P_3$ of quadrants $Q_2,Q_3$ then the part $P_2$ that lies in the second quadrant gets mapped to $Q_3$ and part $P_3$ that lies in third quadrant gets mapped to $Q_2$

Hope this helps.

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What is the formula for finding the measure of a missing angle on a triangle?

Marat540 [252]

Answer:

Step-by-step explanation:

you add two angles and then subtract it from 180 degrees

Hopefully it is right

for example: A angle+B angle-180 degrees

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3 years ago

List seven guidelines that will help you plan a working budget.

Nutka1998 [239]

Gather financial details, list all sources of income, categorize expenses, list supplies, other expenses, calculate overall cost and subtract from your income, if needed tweak budget.

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4 years ago

find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

6 0

3 years ago

Taylor and Nora go to the movie theater and purchase refreshments for their friends. Taylor spends a total of $69.00 on 6 drinks

fgiga [73]

Answer:

The system if equation that can be used to derive this are

6x + 4y = 69 AND

12x + y = 96

The price of a drink is $7.5

Step-by-step explanation:

The question here says that Taylor and Nora went to the movie theater and purchase refreshments for their friends. Taylor spends a total of $69.00 on 6 drinks and 4 bags of popcorn Nora spends a total of $96.00 on 12 drinks and bag of popcorn.And we are now told to write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn. Using these equations,we should determine and state the price of a drink, to the nearest cent .

Now, Let's assume that the price of a drink is "X" and that of a bag of popcorn to be Y

The first person made a purchase which led to the equation

6x + 4y = 69______ equation 1

And the second person also made a purchase that lead to the equation

12x + y = 96_____ equation 2

We make y the subject of the formula in equation 2 and apply it in 1

Y = 96 - 12x

Now apply the above in equation 1

6x + 4y = 69

6x + 4(96 - 12x)= 69

6x + 384 - 48x = 69

42x = 384 - 69

X = 315/42

X = 7.5

Substitute x= 7.5 in equation 2

12x + y = 96

12(7.5) + y = 96

90 + y = 96

Y = 6

Therefore, the price of a drink is $7.5

4 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER

erastova [34]

Answer:

B. y = -1/2x

Step-by-step explanation:

Because the answer is in point-slope intercept form, we know -1/2 is m. Also, because the equation is setting y equal to x, we know it goes through the origin.

3 0

3 years ago