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a_sh-v [17]
3 years ago
7

Solve for x x + 6=18

Mathematics
1 answer:
Verizon [17]3 years ago
6 0
X=12

This is because you subtract 6 from both sides to get the x isolated.

So x=18-6

x=12 :)
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Grace has a 15 inch diameter bicycle tire. How many revolutions will it make traveling 500 feet?
Brums [2.3K]

Answer:

Revolution = 127.24 revolutions

Step-by-step explanation:

<em><u>Circumference of the tire = πD</u></em>

Where D = 15 inch

So,

C = 15π = 47.1 inch

<u><em>In feets:</em></u>

47.1 inch = 3.93 feet.

So, <u>one revolution = 3.93 feet</u>

<u><em>Travelling 500 feet will make the following revolutions:</em></u>

Revolution = 500 feet/3.93 feet

Revolution = 127.24 revolutions

5 0
2 years ago
Moira solved a problem on the board. What error did Moira make and how can she correct it?
Sati [7]

Answer:

C

Step-by-step explanation:

What you do on one side of the equation, you do to the other. She added 10x on the right side and subtracted 10x on the left when she should have added 10x on both sides.

3 0
3 years ago
Please answer it quickly the question is below!!! 40 points!!!!
andrew-mc [135]

Answer:

187.5 ft

Step-by-step explanation:

50 ft x 3.75 = 187.5

8 0
3 years ago
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
Find the slope and y-intercept of each equation y=3x-2
alina1380 [7]

Step-by-step explanation:

Slope = 3 (Coefficient of x)

y-intercept = -2

4 0
3 years ago
Read 2 more answers
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