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Trava [24]
3 years ago
14

PLEASE HELP I'LL GIVE BRAINLIEST

Mathematics
1 answer:
ivanzaharov [21]3 years ago
8 0

Okay, so I multiplied the feet in height of the shape, and I ended up getting 7,125. I hope this helps you out!

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Find the range of f(x)=-2x+6 for the domain {-1, 3, 7, 9}
velikii [3]

Answer:

8, 0, -8, -12

Step-by-step explanation:

3 0
3 years ago
Find the volume of the cylinder.<br> Either enter an exact answer in terms of π or use 3.14
Grace [21]
Correcto 32 8 x 2 x 2=32
 
7 0
2 years ago
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PLEASE HELP ASAP WILL MARK THE BRAINLEST
statuscvo [17]

Answer:

similar triangles

Step-by-step explanation:

First of all, what are similar shapes? Well, two shapes are similar if you can turn one into the other by moving, rotating, flipping, or scaling. That means you can make one shape bigger or smaller. In this case, we know that triangles ABC and DEF are mathematically similar. The area of triangles ABC is , so we need to know the area of triangle DEF.

From math, let's call  the scaling factor, so we know that for any similar figures, the ratio of the areas of any are in proportion to . In other words, if  is the area of triangle ABC, and  is the area of triangle DEF, then we can write the following relationship:

4 0
2 years ago
Find the product of<br> (x2 + 3x + 1)(x2 + x + 2)
Bogdan [553]

Answer: x^4+4x^3+6x^2+7x+2

Step-by-step explanation:

To solve the exercise you must apply the following proccedure:

- Apply the distributive property.

- Keep on mind that when you multiply two powers with equal base, you must add the exponents.

- Add like terms.

Therefore, you obtain the following product:

=x^{(2+2)}+x^{(2+1)}+2x^2+3x^{(1+2)}+3x^{(1+1)}}+6x+x^{2}+x+2\\=x^4+x^3+2x^2+3x^3+3x^2+6x+x^2+x+2\\=x^4+4x^3+6x^2+7x+2

4 0
3 years ago
Read 2 more answers
I am having trouble with this problem. I need to find the lengths of this right triangle. How would you do this?
podryga [215]
You labeled the triangle wrong sides 'a' and 'b' are supposed to be the sides that make the right angle.  the other side is called the hypotenuse which is the longest side which you should have labeled 'c'

so Pythagorean theorem says
a^2+b^2=c^2
so
(2x+1)^2+(11x+5)^2=(12x+1)^2
distribute
(4x^2+4x+1)+(121x^2+110x+25)=(144x^2+24x+1)
add like terms
125x^2+114x+26=144x^2+24x+1
subtract 125x^2 from both sides
114x+26=19x^2+24x+1
subtract 114x from both sides
26=19x^2-90x+1
subtract 26 from both sides
0=19x^2-90-25
factor
(x-5)(19x+5)=0
therefor x-5=0 and/or 19x+5=0
so
x-5=0 add 5 to both sides
x=5
19x+5=0
subtract 5 from both sides
19x=-5
divide both sides by 19
x=-5/19
since side legnths can't be negative, we can cross this solution out

so x=5
subtitute
1+2x
1+2(5)
1+10=11
side a=11

11x+5
11(5)+5
55+5=60
side b=60

12x+1
12(5)+1
60+1=60
side c=61
add them all up
side a+b+c=11+60+61=132=total legnth
5 0
2 years ago
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