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Reptile [31]
3 years ago
9

What are the solutions to the system of equations?

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0

The answer is definitely C

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Write <img src="https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-x-3%2Bx%5E%7B3%7D" id="TexFormula1" title="3x^{2} -x-3+x^{3}" alt="3x^{2
Elza [17]

Answer:

Standard form: x^3+3x^2-x-3

Leading coefficient: 1

Step-by-step explanation:

3x^2-x-3+x^3=\\x^3+3x^2-x-3

The leading coefficient is 1 because the leading term is x^3.

5 0
2 years ago
Please answer this correctly
Ymorist [56]

B; 25.65+13.23+6.35=45.23

To do this mentally just add the 2 decimals places together first (1.23). Then just add the whole numbers (44). Then add the 2 numbers together, 44+1.23=45.23

8 0
3 years ago
What are prime factors of 1000?
Ede4ka [16]

Answer:

1,2,4,5,8,10,20,25,40,50,10,125,200,250,500,1000

Step-by-step explanation:

prime factorization is

1000=2*2*2*5*5*5

4 0
2 years ago
How many degrees is 1/4 of a circle?
irina1246 [14]
45 degrees is the answer to your problem

5 0
3 years ago
Read 2 more answers
2. A lunch stand makes s.75 profit on each chef's salad and $1.20 profit on each Caesar salad. On a typical weekday, it sells be
kow [346]

Let's let

<u>x = the number of chef salads, x>=0</u>

<u>y = the number of Caesar salads, y>=0</u>

The constrains are:

40 <= x <= 60

35 <= y <= 50

x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35),  (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

F (60, 40) = 0.75*60 + 1.20*40 = $93

F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

8 0
3 years ago
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