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erastovalidia [21]
3 years ago
9

QUESTION

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
1. For this item we just refer to the prompt to know the conjectures of Ernest and Denise. According to Ernest, they should swim 1 kilometer on the first week then add 0.25km every week while Denise believes that they should swim 1 kilometer on the first week then add 0.5km every week.

2. Yes, these distances make an arithmetic sequence. It's because an arithmetic sequence is defined as a group of increasing or decreasing numbers where the difference between any two consecutive numbers is constant. This just means that every number has the same interval. In the case of their schedule, this is true.

3. For this item we just follow the descriptions of Ernest's and Denise's schedule in item number 1. For Ernest, we just keep adding 0.25 from 1 kilometer until we added it thrice. For Denise, we also keep adding a number thrice but this time it's 0.5 instead of 0.25.

Ernest's Schedule: 1, 1.25, 1.5, 1.75
Denise's Schedule: 1, 1.5, 2, 2.5

4. Here we are asked to determine a formula that will describe the schedules of Ernest and Denise. In the given formula a_{n}= a_{n-1}+d, a_{n} refers to the next term in the sequence, a_{n-1} refers to the previous term, while d refers to the common difference. In the recursive formula all we need is to insert the value of d to the equations.

Ernest: a_{n}= a_{n-1}+0.25
Denise: a_{n}= a_{n-1}+0.5

5. For this item we basically do the same thing but this time we are given another formula. Our formula is in the form a_{n}= a_{1}+(n-1)d where a_{n} is still the nth term of the sequence, a_{1} is the very first time, n is the number of terms, and d is the common difference. 

Ernest: a_{n}= 1.0+0.25(n-1)
Denise: a_{n}= 1.0+0.5(n-1)

6. In this item we will just basically substitute numbers to one of the equations that we've set up in item #5. For this we need Ernest's explicit formula first. To know how far they will be swimming on week 10, the number of elements (n) must be 10.

a_{10}= 1.0+0.25(10-1)
a_{10}= 1.0+0.25(9)
a_{10}= 1.0+2.25
a_{10}= 3.25

7. Here, we just do the same thing as item #6 but this time we will consider Denise's explicit formula. Since we are also asked how far the students will be swimming on week 10, the number of elements would also be 10 and this would also be our value for n.

a_{10}= 1.0+0.5(10-1)
a_{10}= 1.0+0.5(9)
a_{10}= 1.0+4.5
a_{10}= 5.5

8. The answer for this question is obvious. You would just need to look at the 10th element in Ernest's and Denise's sequences and tell whose schedule had more than or equal to 5 as an answer. Following Ernest's schedule, you will just get 3.5 kilometers on the 10th week so it's definitely a no. Denise's schedule, on the other hand, would get you to 5.5 kilometers on week 10 so her training schedule should be followed.
Bdbhdjdjsjs
3 years ago
What’s 8 ?
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3 0
3 years ago
If x+y = z and y−z=x which of the following must be equal to z?
umka21 [38]

<u>ANSWER</u>

(C) y

<u>EXPLANATION</u>

We have two equations:

The first one is

x + y = z...(1)

The second equation is

y - z = x...(2)

Let us make z the subject of this second equation:

\implies \: -x +y = z...(3)

We now add equation (1) and (3) to get:

(-x + x) + (y +  y) = z + z

We simplify to get:

0+2y= 2z

2y= 2z

Divide throu by 2.

\frac{2y}{2}  =  \frac{2z}{2}

y= z

\therefore \: z = y

The correct answer is C

8 0
4 years ago
If you place a 29-foot ladder against the top of a building and the bottom of the ladder is 16 feet from the bottom of the build
Anettt [7]

Answer:

24.2 feet.

Step-by-step explanation:

pythagorean theorem will solve this so A^2 + B^2=C^2

we have a and c so you do c -a and square root it to get your answer

4 0
3 years ago
Regina’s work to find the surface area of a square pyramid from its net is shown below.
Y_Kistochka [10]

She put 12.8 in place of 11.9 in the formula of the triangle. Then the correct option is A.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Regina’s work to find the surface area of a square pyramid from its net is shown below.

A square pyramid. The square base has side lengths of 9.4 inches. The triangular sides have a height of 11.9 inches.

Surface area of the pyramid = 4 [one-half (9.4) (12.8)] + 9.4² = 329 square inches

Then the error done by Regina will be

She should have used One-half (9.4) (11.9) to represent the area of a single triangle.

Then the correct option is A.

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

7 0
2 years ago
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