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erastovalidia [21]
3 years ago
9

QUESTION

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
1. For this item we just refer to the prompt to know the conjectures of Ernest and Denise. According to Ernest, they should swim 1 kilometer on the first week then add 0.25km every week while Denise believes that they should swim 1 kilometer on the first week then add 0.5km every week.

2. Yes, these distances make an arithmetic sequence. It's because an arithmetic sequence is defined as a group of increasing or decreasing numbers where the difference between any two consecutive numbers is constant. This just means that every number has the same interval. In the case of their schedule, this is true.

3. For this item we just follow the descriptions of Ernest's and Denise's schedule in item number 1. For Ernest, we just keep adding 0.25 from 1 kilometer until we added it thrice. For Denise, we also keep adding a number thrice but this time it's 0.5 instead of 0.25.

Ernest's Schedule: 1, 1.25, 1.5, 1.75
Denise's Schedule: 1, 1.5, 2, 2.5

4. Here we are asked to determine a formula that will describe the schedules of Ernest and Denise. In the given formula a_{n}= a_{n-1}+d, a_{n} refers to the next term in the sequence, a_{n-1} refers to the previous term, while d refers to the common difference. In the recursive formula all we need is to insert the value of d to the equations.

Ernest: a_{n}= a_{n-1}+0.25
Denise: a_{n}= a_{n-1}+0.5

5. For this item we basically do the same thing but this time we are given another formula. Our formula is in the form a_{n}= a_{1}+(n-1)d where a_{n} is still the nth term of the sequence, a_{1} is the very first time, n is the number of terms, and d is the common difference. 

Ernest: a_{n}= 1.0+0.25(n-1)
Denise: a_{n}= 1.0+0.5(n-1)

6. In this item we will just basically substitute numbers to one of the equations that we've set up in item #5. For this we need Ernest's explicit formula first. To know how far they will be swimming on week 10, the number of elements (n) must be 10.

a_{10}= 1.0+0.25(10-1)
a_{10}= 1.0+0.25(9)
a_{10}= 1.0+2.25
a_{10}= 3.25

7. Here, we just do the same thing as item #6 but this time we will consider Denise's explicit formula. Since we are also asked how far the students will be swimming on week 10, the number of elements would also be 10 and this would also be our value for n.

a_{10}= 1.0+0.5(10-1)
a_{10}= 1.0+0.5(9)
a_{10}= 1.0+4.5
a_{10}= 5.5

8. The answer for this question is obvious. You would just need to look at the 10th element in Ernest's and Denise's sequences and tell whose schedule had more than or equal to 5 as an answer. Following Ernest's schedule, you will just get 3.5 kilometers on the 10th week so it's definitely a no. Denise's schedule, on the other hand, would get you to 5.5 kilometers on week 10 so her training schedule should be followed.
Bdbhdjdjsjs
2 years ago
What’s 8 ?
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Answer the following true or false. Justify your answer.
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a) False b) False c) True d) True e) True

Step-by-step explanation:

a) If A is a subset of B, and x∈B, then x∈A. False

Suppose A is Z (Set of Integers), and B is R (Set of Real Numbers). Then A is a subset of B. x ∈ B, let's say x equals π. If x ∈ B (B = Real Numbers) and x=π then x ∉ A (Z).

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For this one, I've drawn some lines, and it is useful to work with them.

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En la casa de Juan, van a pedir pizza para la comida, pero cuando la van a pedir se dan cuenta que deben pedirla por perímetro o
Degger [83]

Responder:

La pizza con un perímetro de 100 cm es más grande ¿verdad?

Explicación paso a paso:

Deja que la pizza tenga forma circular.

Sea el área de la pizza = πd² / 4 y;

Perímetro de la pizza = πd

d es el diámetro de la pizza

Si la madre dice que el que tiene un perímetro de 100 cm es más grande, para estar seguros necesitamos obtener el diámetro de la pizza. La de mayor diámetro será la pizza más grande.

P = 100cm

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d = 100 / π

d = 100 / 3,14

d = 31,85 cm

El diámetro de la pizza mamá es de 31,85 cm.

Si el padre dice que el que tiene un área de 100 cm² es más grande, obtengamos también el diámetro para estar seguros.

A = πd² / 4

100 = πd² / 4

400 = πd²

d² = 400 / π

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d = √127,39

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Por lo tanto, el diámetro de la pizza padre es de 11,29 cm.

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