61 quaters
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Add the who numbers: 4 + 2 = 6
You are correct, it's C. 6
The interquartile range is from Q1 to Q3 and to get this you have to subtract Q2 by Q3. The 10 units represent that only 10 units are fit in the given range.
Answer:
Step-by-step explanation:
X( -9 , 2) & Y(5 , -4)
![distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\XY=\sqrt{(5-[-9])^{2}+(-4-2)^{2}}\\\\=\sqrt{(5+9)^{2}+(-6)^{2}}\\\\=\sqrt{(14)^{2}+(-6)^{2}}\\\\=\sqrt{196+36}\\\\=\sqrt{232}\\\\= 15.23](https://tex.z-dn.net/?f=distance%20%3D%20%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5CXY%3D%5Csqrt%7B%285-%5B-9%5D%29%5E%7B2%7D%2B%28-4-2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%285%2B9%29%5E%7B2%7D%2B%28-6%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%2814%29%5E%7B2%7D%2B%28-6%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B196%2B36%7D%5C%5C%5C%5C%3D%5Csqrt%7B232%7D%5C%5C%5C%5C%3D%2015.23)
The answer your are looking for is true