Answer:
Step-by-step explanation:
Letting "a" and "c" represent the costs of adult tickets and child tickets, the problem statement gives us two relations:
3a +5c = 52
2a +4c = 38
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We can solve this system of equations using "elimination" as follows:
Dividing the first equation by 2 we get
a +2c = 19
Multiplying this by 3 and subtracting the first equation eliminates the "a" variable and tells us the price of a child ticket:
3(a +2c) -(3a +4c) = 3(19) -(52)
c = 5 . . . . . . collect terms
a +2·5 = 19 . . substitute for c in the 3rd equation above
a = 9 . . . . . . subtract 10
One adult ticket costs $9; one child ticket costs $5.
Answer: Both trains would meet at 1 pm
Step-by-step explanation:
Let t represent the time at which both trains will pass each other.
The distance between the cities is 360 miles. This means that by the time both trains meet, the total distance covered would be 360 miles.
Distance = speed × time
The freight train is travelling at 50 mph. Distance covered by the freight train in t hours is 50t.
The passenger train is travelling at 70 mph. Distance covered by the passenger train in t hours is 70t.
Since the total distance covered is 360 miles, it means that
50t + 70t = 360
120t = 360
t = 360/120
t = 3 hours
Both trains would meet at 1 pm
4/5 ,8/10, 16/20,
You multiply both numbers with the same number.
For ex. 4×2=8 5×2=10 so we have 8/10
Answer:
6/3 or 2 (you should probably write 2 though)
(there’s a couple notes in the pic too that will help you with slopes)
