The sides of a triangle measures 7,8, and 12. Which type of triangle is it?

Simplify the expression.(–12m 38)

Ludmilka [50]

-6m+19
1/2(-12m+38) All we have to do is simply distribute the 1/2. 1/2(-12m) + 1/2(38) (-6m) + 19

5 0

3 years ago

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There are 3 cups of blue paint and 2 cups of red paint. Whats the ratio?

steposvetlana [31]

Answer:

3:2

Step-by-step explanation:

can also be written as 3/2 as a fraction!

7 0

2 years ago

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Complete the table for the given rule y=1/3x i dont have a calculator

Licemer1 [7]

Do up one over 3 and start at 0, that is what I recommend

5 0

3 years ago

Let v be a vector with initial point (-5, -11) and terminal point (6,2). What is v?

White raven [17]

Answer-The vector is

=

7

→

i

−

24

→

j

and the magnitude is

=

25

Explanation:

Let the point

A

=

(

−

2

,

7

)

and

B

=

(

5

,

−

17

)

Then,

−−→

A

B

=

(

5

−

(

−

2

)

−

17

−

7

)

=

(

7

−

24

)

The magnitude of

−−→

A

B

is

∣

−−→

A

B

∣

=

√

(

7

)

2

+

(

−

24

)

2

=

25

Step-by-step explanation:

4 0

2 years ago

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Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always

NeTakaya

Answers:

A) $-\frac{11}{4}$

C) $m_{1}=\frac{Fr^{2}}{G m_{2}}$

Step-by-step explanation:

Part 1:

We have the followig equation:

$\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}$

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

$\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}$

Solving for the left part of the equation:

$\frac{2x-17}{15}=\frac{4x-1}{8}$

Operating with cross product:

$8(2x-17)=15(4x-1)$

Applying the distributive property:

$16x-136=60x-15$

Isolating $x$ :

$x=-\frac{121}{44}$

Dividing numerator and denominator by 11:

$x=-\frac{11}{4}$ Hence, the correct option is A

Part 2:

We have the followig equation:

$F=\frac{G m_{1} m_{2}}{r^{2}}$

Operating with cross product:

$Fr^{2}=G m_{1} m_{2}$

Isolating $m_{1}$ :

$m_{1}=\frac{Fr^{2}}{G m_{2}}$ Hence, the correct option is C

5 0

3 years ago