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KiRa [710]
4 years ago
11

A sequence of transformations maps triangle ABC to triangle A’B’C’. The sequence of transformations that maps triangle ABC to tr

iangle A’B’C’ is a reflection across the
- y-axis
- x-axis
- line y=x
OR - line y=-x

...followed by a translation

- 4 units to the right and 10 units up
- 8 units to the right and 10 units up
- 10 units to the right and 2 units up
OR - 10 units to the right and 4 units up.

Mathematics
1 answer:
Zolol [24]4 years ago
6 0

Answer:

Reflection across the line y=x followed by translation 10 units to the right and 4 units up.

Step-by-step explanation:

Triangle ABC has vertices at points A(-6,2), B(-2,6) and C(-4,2).

1. The reflection across the line y=x has the rule

(x,y)→(y,x).

Thus,

  • A(-6,2)→A''(2,-6);
  • B(-2,6)→B''(6,-2);
  • C(-4,2)→C''(2,-4).

2. The translation 10 units to the right and 4 units up has the rule

(x,y)→(x+10,y+4).

Thus,

  • A''(2,-6)→A'(12,-2);
  • B''(6,-2)→B'(16,2);
  • C''(2,-4)→C'(12,0).

Points A'B'C' are exactly the vertices of the triangle A'B'C'.

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You can model an arch at your school using the equation y=−0.9(x+3)(x−3), where x and y are measured in feet. The x-axis represe
Slav-nsk [51]

Answer:

6 ft

Step-by-step explanation:

As we know that, the arch meet the ground are the value of x when y = 0

y=−0.9(x+3)(x−3)

<=> 0 = −0.9(x+3)(x−3)

<=> x=3 or x=-3  

So we have 2 coordinates: (3, 0) and (-3,0) and the distance between them is:

3 -(-3) = 6

=> The width of the arch at ground level is 6 ft

7 0
3 years ago
A decibel is a logarithmic unit that can be used to measure the intensity of a sound. The function y = 10logx gives the intensit
Anna007 [38]

Answer:

The sound intensity of a whisper is 333.3 times the reference intensity

Step-by-step explanation:

Given : The function y = 10logx gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity.

A whisper has a sound intensity of 30 decibels.

To find : Use your graph to help you complete the following statement. The sound intensity of a whisper is times the reference intensity.

Solution :

Graph is attached which shows their intersection at (1000,30).

We can also verify by substituting value.

We have given that a whisper has a sound intensity of 30 decibels.

Therefore, y=30 , Let log base 10

y = 10logx

30 = 10logx                              

\frac{30}{10} =logx

3=logx

Logarithmic property log_{x}b=a \Rightarrow b=x^a

x=10^3

x=1000

The ratio of the intensity of the sound to a reference intensity is 1000 decibels

The sound intensity of a whisper is times the reference intensity is

\frac{1000}{3}=333.33

The sound intensity of a whisper is 333.3 times the reference intensity.

7 0
3 years ago
Read 2 more answers
And this one too!! Thanks in advance
Harlamova29_29 [7]

Answer:

20/9 sq.feet

Step-by-step explanation:

The width is 4/3 ft because 1/3 times 4 is 4/3 and the length is 5/3 because 1/3 times 5 is 5/3.

Then to find the area you do length times width.

5/3 ×4/3= 20/9 sq. feet


I hope this helps! :)

3 0
4 years ago
Solve 7x + 12 = 3x <br><br>Solve for x​
Maslowich

Answer:

= − 3

thats the asnwer

7 0
3 years ago
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The overall length would be 6in
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