Answer:
0.1587
Step-by-step explanation:
Here, mean=μ=100 and standard deviation=σ=16.
We have to find P(average MDI scores of 64 children > 102)=P(xbar>102).
n=64
μxbar=μ=100
σxbar=σ/√n=16/√64=16/8=2
P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)
P(xbar>102)=P(z>1)
P(xbar>102)=P(0<z<∞)-P(0<z<1)
P(xbar>102)=0.5-0.3413
P(xbar>102)=0.1587
Thus, the probability that the average is greater than 102 is 15.87%
Answer:
7/100
Step-by-step explanation:
Find the GCD (or HCF) of numerator and denominator
GCD of 70 and 100 is 10
Divide both the numerator and denominator by the GCD
70 ÷ 10
100 ÷ 10
Reduced fraction:
7
10
Therefore, 70/100 simplified to lowest terms is 7/10.
Answer: i dont see a thing yur thing isnt
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Step-by-step explanation:
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