Answer:
C-value is the amount, in picograms, of DNA contained within a haploid nucleus or one half the amount in a diploid somatic cell of a eukaryotic organism.
-5/4 ÷ 2 3/5
Let's turn 2 3/5 into a complete fraction so multiply bottom by two and add it to the top. Take the answer and put it over the original bottom. SO: 13/5
Now KEEP CHANGE FLIP
keep -5/4
change sign to ×
flip 13/5 to 5/13
Thus: -5/4 × 5/13
Simply, multiply
-25/52
Done, hope that helps :)
You would see the square root of 13 and it would be 3.60 which squared would make 12.96 so round up and you will get 13
Answer: The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Step-by-step explanation:
We know that the intensity of electromagnetic waves decreases with the radius squared, this means that we can write a simple relation as:
Intensity(r) = A/r^2
Observer A measures 16 the intensity of observer B.
if Ia is the intensity that observer A measures and Ib is the intensity that observer B measures, we have that:
Ia = 16Ib
A/(ra)^2 = 16*A/(rb)^2
1/(ra)^2 = 16/(rb)^2
rb^2 = 16*ra^2
and we know that 16 = 4*4 = 4^2
rb^2 = (4*ra)^2
then rb = 4*ra
this means that the distance between observer B and the antenna is equal to 4 times the distance between observer A and the antenna.
The fraction is ra = rb/4
The distance of
Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
