Answer:
The water level is dropping at a rate of 0.24 ft/s
Step-by-step explanation:
Here, we simply want to calculate the change in depth (height of the cone) , given the volume change
Mathematically, we have the volume of a cone as;
V = 1/3 * π * r^2 * h
we are given dv/dt as 12 ft^3/m
dv/dh = 1/3 * π * r^2
Substituting the value for the radius, we have
dv/dh = 1/3 * 22/7 * 4^2 = 50.29
dh/dt = dh/dv * dv/dt
dh/dv = 1/(dv/dh) = 1/50.29
Thus,
dh/dt = 1/50.29 * 12
dh/dt = 0.24 ft/s
The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...
The mean is centered among the other numbers in both sets of data.
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The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.
Answer:
g. 3+2 =5
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The two horizontal lines are parallel ( This is given by the red triangles)
Because the lines are parallel, the two angles 1 & 2 would be the same.
Set the two equations for the angle to equal each other and solve:
8y-6 = 7y
Add 6 to each side:
8y = 7y+6
Subtract 7y from each side:
y = 6
Now you have the value for y, solve for angle 2 by replacing y with 6:
Angle 2 = 7y = 7(6) = 42 degrees.
