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rjkz [21]
2 years ago
12

Find the missing dimensions: Use the scale factor 1/4:3

Mathematics
2 answers:
katrin [286]2 years ago
8 0

Answer:

The answer is 1/4!

Step-by-step explanation:

Irina18 [472]2 years ago
8 0
I believe it’s 1/4 I’m not sure sorry if I’m wrong
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Whats is the difference between a factor and multiple
Deffense [45]

Answer:

<h3> a factor is a number that divides another number without leaving any remainder. , A multiple is a number that, when divided a certain of times by another number, no remainder is left.</h3>

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
Plz tell me this solution it's very urgent​
a_sh-v [17]

Step-by-step explanation:

here is fig 15

x=36 (v.o.a are equal)

36+y=180

y=180-36=144

y=z=144 vertically

3 0
3 years ago
How do you find the arctan 4/3 ? (Without a calculator)
Soloha48 [4]
If arctan 4/3 = the tangent of that angle will be 4/3 , opposite 4 over adjacent 3

Now, you only have to take the sin of that angle it's opposite 4 over hypotenuse 5. 

You will get that the answer is 4/5

hope this helps



7 0
2 years ago
How to answer because I struggle to answer
SpyIntel [72]

5: AA  47=47    36=36  similar

6: SSS   32/16 =2,  24/12 =2,  9/4.5 = 2  similar    

7: SAS  72/53= 1.3,  55=55, 48/12 = 4  not similar

8: SAS  45/15= 3,  54=54,  9/3=3  Similar

9.SAS  20/10 =2,  10/8 = 1.25  not similar

10.SAS  32/14= 2.29, 46=46,  12/7= 1.79  not similar


5 0
3 years ago
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