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3 years ago

Help me with this quick pleaseeeee

Mathematics

1 answer:

melisa1 [442]3 years ago

3 0

Answer:

D' = ( 1 , -1 )

Step-by-step explanation:

2 times 1/2 = 1

-2 times 1/2 = -1

hope this helps ^^

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Find the value of 2a squared + 5b squared when a = -6 and b =2

jenyasd209 [6]

given 2a² + 5b²

substitute given values for a and b into the expression

2(- 6)² + 5(2)² = (2 × 36 ) + (5 × 4) = 72 + 20 = 92

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3 years ago

Find the missing side of this right

navik [9.2K]

Answer:

x = 13

Step-by-step explanation:

First start with the blank equation

$a^{2} + b^{2} = c^{2}$

Plug in the legs and hypotenuse. Remember c squared is always the hypotenuse.

$5^{2} + 12^{2} = c^{2}$

Then solve

25 + 144 = $c^{2}$

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3 years ago

A bicycle tire is 28 inches in diameter.Approximately how far does the bicycle move forward each time the wheel goes around?(use

Debora [2.8K]

Answer:

88 Inches

Step-by-step explanation:

For any bicycle tire of a given diameter, the approximate distance moved by the bicycle each time the wheel goes around is determined by the circumference of the circular wheel.

Since the diameter =28 Inches

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The bicycle moves 88 Inches forward each time the wheel goes around.

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3 years ago

Evaluate 7(m-11) if m =11

melamori03 [73]

Answer:

Step-by-step explanation:

Plug in 11 for m. Remember to follow PEMDAS. First solve the parenthesis, then multiply.

m = 11

7(m - 11) = 7(11 - 11) = 7(0) = 0

0 is your answer.

7 0

3 years ago

Read 2 more answers

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

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3 years ago