Step-by-step explanation:
<u>Formula:</u>
r represents the radius.
The radius is 1/2 of the diameter.
Since 1/2 of 16 is 8, 8 is our radius.
<u>Substitute:</u>
<u>Solve:</u>
Answer:
Program C allows students to earn a Mathematics degree (B.A. or B.S.) by combining courses in the Department of Mathematics with courses from one other department. In most areas of specializations, mathematical and/or quantitative courses in other departments are part of the math degree program. All Program C students take a minimum of five core math courses: Calculus I, Calculus II, Calculus III, Introduction to Linear Algebra, and a proofs course, usually either Introduction to Abstract Algebra or Fundamental Properties of Spaces and Functions I.
Step-by-step explanation:
n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
Answer:
Step-by-step explanation:
Join A and C and B and D. And add numbers to the angles formed on one of the diagonal
In triangles ABC and ADC,
Angle 1 = Angle 4
Angle 3 = Angle 2
AC = AC
Therefore, triangle ABC=ADC
Since, ABC=ADC
Similarly, triangle ABD= triangle CDB
Therefore, AB=CD and BC=DA