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3 years ago

Tim is reading a book that contains 55 pages .He has read 46 pages,How many pages are unread?

Mathematics

2 answers:

Semenov [28]3 years ago

5 0

55-46=9 The answer is 9 unread pages

WINSTONCH [101]3 years ago

5 0

Answer:

9 unread pages

Step-by-step explanation:

Take the total number of pages and subtract the pages that have been read

55-46 = 9

There are 9 pages that are unread

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Please help me i will give Brainly

Degger [83]

Answer:

Step-by-step explanation:

$\frac{3x + 5}{2x + 7}$ = 5

do cross multiplication

3x + 5 = 5(2x + 7)

3x + 5 = 10x + 35

5 - 35 = 10x - 3x

-30 = 7x

-30/7 = x

20 A

since there are 7 angles given it means that the polygon is heptagon as heptagon has 7 sides.

sum of interior angle of heptagon = (n-2)*180

(7-2)*180

5*180

900

Now ,

110 + 90 + 150 + 102 + 110 + 170 + x = 900

732 + x = 900

x = 900 - 732

x = 168 degree

20 B

since 5 angles are given it means that the polygon is pentagon as pentagon has 5 sides.

sum of interior angles of a pentagon = (n-2)*180

(5-2)*180

3*180

540 degree

Now ,

110 + 95 + 120 + 114 + x = 540

465 + x = 540

x = 540 - 465

x = 75 degree

let one rational number be x

according to the question,

1/7 * x = 2

x/7 = 2

do cross multiplication

x = 14

6 0

3 years ago

Simplify.

elena55 [62]

$\dfrac{4}{10}-\dfrac{2}{15}=\dfrac{4\cdot 15-10\cdot 2}{10\cdot 15}\\\\=\dfrac{40}{150}=\dfrac{4}{15}$

The correct choice appears to be ...

... A) 4/15

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME ASAP!!!

rjkz [21]

Answer:

d) $7^{14}$

Step-by-step explanation:

we simplify $(7^{7})^{2}$ by doing 7 x 2 = 14

so it is now

$7^{14}$

to check, we can use a calculator.

7 to the power of 14 = 678223072849

and

7 to the power of 7, squared also = 678223072849

Hope this helps!

7 0

2 years ago

Solve -7x^2+x+9=-6x quadratic formula

myrzilka [38]

Answer:

$-7x^2+x+9=-6x$

$-7x^2+x+9+6x=-6x+6x$

$-7x^2+7x+9=0$

$quadratic\: formula$

$x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}$

$\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}$

$x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}$

$\frac{-7+\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7+\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7+\sqrt{301}}{-14}$

$\frac{-7-\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7-\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7-\sqrt{301}}{-14}$

$answer=\frac{7+\sqrt{301}}{14}$

$OAmalOHopeO$

7 0

3 years ago

AleksAgata [21]

$\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432$

3 0

3 years ago