Answer:
Step-by-step explanation:
h = 5 ft
diameter = 2.4 ft
Radius is half of diameter
r = 2.4/2 = 1.2 ft
Now, find the volume of the tank
Volume = πr²h
= 3.14 * 1.2 *1.2 * 5
= 22.608 cubic ft
Time taken to fill the tank = Volume of tank ÷ volume of gas filled per minute
= 22.608 ÷ 2.3
= 9.8
= 10 minutes
Answer:
x = 15
Step-by-step explanation:
by solving;
- 4x + 8x +14 -14 = 180
- 12x = 180
- x = 180 / 12
- x = 15
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em><em>^</em><em>_</em><em>^</em>
Answer:
Rs 17 3/4
Step-by-step explanation:
Cost of 6 1/2 m = 115 3/8
Cost of 1 m = x
- x = 115 3/8 ÷ 6 1/2
- x = (115*8 +3)/8 ÷ 13/2
- x = 923/8 × 2/13
- x = 923/(4*13)
- x = 923/52
- x = 17 39/52
- x = 17 3/4
Cost of 1 meter is Rs 17 3/4
This question is incomplete
Complete Question
An arts academy requires there to be 6 teachers for every 132 students and 4 tutors for every 44 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 132 students?
Answer:
a)How many students does the academy have per teacher?
22 students per teacher
b) Per tutor?
11 students per tutor
c) How many tutors does the academy need if it has 132 students?
12 tutors
Step-by-step explanation:
a)How many students does the academy have per teacher?
6 teachers = 132 students
1 teacher = x
6 × x = 132 × 1
x = 132 × 1/6
x = 22 students
Hence, we have 22 students per tutor
b) Per tutor?
4 tutors = 44 students
1 tutor = x students
Cross Multiply
4 × x = 1 × 44
x = 44/4
x = 11 students
Hence, we have 11 students per tutor
c) How many tutors does the academy need if it has 132 students?
44 students = 4 tutors
132 students = x tutors
Cross Multiply
44 × x = 132 × 4
44x = 132 × 4
x = 132 × 4/44
x = 12 tutors
The academy needs 12 tutors if they have 132 students.
Answer:
y = 130/3 + 5
Step-by-step explanation:
(0,5) (1,15) (2,45) (3,135)
