The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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Well this problem can be solved with Algebra
the rule here is that for every incrementing sequence you increase your number by 6.
T(n)=18+6(n-1)
for 603 to be in the sequence, it has to male sense with the function above
603=18+6(n-1)
603-18=585
585=6(n-1)
n-1=(585/6)
n=(585+6)/6
n=591/6
here is your answer.
Answer:
3 to the 4th power.
Step-by-step explanation:
Basically, here 3 to the 3rd power is 27. Multiplying it by 3 is only adding another power, making it 81, which is the same answer to 3 to the 4th power if that makes sense.
3 1/2 - (2/3)(3 1/2) =
<span>7/2 - (2/3)(7/2) = </span>
<span>7/2 - 7/3 = </span>
<span>21/6 - 14/6 = </span>
<span>7/6 or 1 1/6 yds</span>
The equation of a circle is written as ( x-h)^2 + (y-k)^2 = r^2
h and k is the center point of the circle and r is the radius.
In the given equation (x+3)^2 + (y-1)^2 = 81
h = -3
k = 1
r^2 = 81
Take the square root of both sides:
r = 9
The center is (-3,1) and the radius is 9
