All categories

3 years ago

Select all that apply.

Mathematics

1 answer:

dimulka [17.4K]3 years ago

3 0

2x 2 - 6x = 0 .... if you mean 2x^2 - 6x = 0
then 2x = 0 and x - 3 = 0 << answer

You might be interested in

A manufacturer of industrial solvent guarantees its customers that each drum of solvent they ship out contains at least 100 lbs

Hitman42 [59]

Answer:

Step-by-step explanation:

Let X be the solvent present

Then given that the manufacturer of industrial solvent guarantees its customers that each drum of solvent they ship out contains at least 100 lbs of solvent.

X is N(101.3, 3.68)

a) $P(X>100) = P(Z>\frac{100-101.3}{3.68} =P(Z>-0.35)\\=0.6368$

Probability = 0.6368

b) $P(X>100)= 0.97$ means Z score = 1.88

X=100+1.88(s) =101.3

s=1.3/1.88=0.6914

4 0

3 years ago

Derek's car has run out of gasoline. He walks 24 km west and then 10 km south looking for a gasoline station. If he is now h km

Juliette [100K]

Answer:

the value of h is √676km

Step-by-step explanation:

The computation of the value of h is shown below

Here we apply the Pythagoreus theorem

= 24^2 + 10^2

= 576 + 100

= √676

Hence, the value of h is √676km

We simply determine by using the Pythagoreus theorem

6 0

2 years ago

The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex

mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

$(6,112,50), (8,150), (11,206.25)$

step 1

Find the slope with the first and second point

$(6,112,50), (8,150)$

$m=(150-112.50)/(8-6)=18.75$

step 2

Find the slope with the first and third point

$(6,112,50), (11,206.25)$

$m=(206.25-112.50)/(11-6)=18.75$

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0

2 years ago

[25 POINTS] The approximate change in the value of f(x) = sqrt(2(x-1)) at x = 3 using differentials with dx = 0.01 is

otez555 [7]

Answer:

$\frac{1}{200}$

Step-by-step explanation:

<u>Find the derivative of the function when x=3</u>

<u /> $y=\sqrt{2(x-1)}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(x-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(3-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(2)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{4}}$

$\frac{dy}{dx}=\frac{1}{2}$

Since the change in the value of the function is $dy$ and we know that the change in x is $dx=0.01$ , then we have:

$\frac{dy}{dx}=\frac{1}{2}$

$dy=\frac{1}{2}dx$

$dy=\frac{1}{2}(0.01)$

$dy=\frac{1}{200}$

Therefore, the 2nd option is correct

<u />

8 0

2 years ago

This is a bit confusing for me, can anyone help me out?

AnnZ [28]

Answer:

circumference=471

area=17671

Step-by-step explanation:

circumference=150pi=150*3.14=471

area=150/2=75 and 75^2pi=5625pi=17671

4 0

2 years ago