triangle ABC is being dilated with center of dialation at the origin. The image of c, point C', has coordinates of (7.2, 3.6). W
hat is the scale factor of the dilation and what are the coordinates of point A'?
2 answers:
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<h3>Given :</h3>
Hence, value of
Answer:
ln\frac{(x-3)^5}{x^2}[/tex]
Step-by-step explanation:
First use the exponent property alnb=ln(b)^a
Then use the difference property that is lna-lnb= ln(a/b)
Answer:
Therefore after 1 second of lunched the object reach a height of 16 feet.
Step-by-step explanation:
When a particle is thrown vertically upward direction on that time only gravitation force is worked on it. In that case the acceleration of the particle is - g.Since gravitation force works downward direction and the displacement of the particle is upward direction that's why acceleration is negative.
When particle comes down the the acceleration of the particle is g.
Since the displacement and acceleration work on the particle in same direction.
The value of g is 9.8 m/s².
Given that, the height of the particle can measure from the equation
Where t is time in second
To find out the time when the object reach a height 16 feet. We have put the value of h in the given equation.
Putting h=16 in the given equation
16= -16 t²+32
⇒16t²-32t+16=0
⇒16(t²-2t+1)=0
⇒t²-2t+1=0² [ ∵16≠0]
⇒(t-1)²=0
⇒t-1=0
⇒t=1
Therefore after 1 second of lunched the object reach a height of 16 feet.