Your answer would be 252 Hope this helps
The triangles are congruent by SAS, so the two angles with 7x and 3x+16 are equal. So
7x=3x+16
4x=16
x=4
So KJL=7(4)=28.
You apply the sum of interior angles formula ie. (n-2)180. n=number of sides
since a pentagon has 5 sides it will be (5-2)180=540.
now add everything. x-5+x-6+2x-7+x+2x-2=540.
Solve for x: 7x-20=540
7x=540+20
7x=560
x=560/7
x=80
Answer:
6x^2 -11x -1
Step-by-step explanation:
(3x^2 + 3) - (6x + 4) + (3x^2 - 5x)
Distribute the minus sign
(3x^2 + 3) - 6x - 4) + (3x^2 - 5x)
Combine like terms
3x^2 + 3x^2 - 6x - 5x -4+3
6x^2 -11x -1