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MAVERICK [17]
3 years ago
10

Which calculation will ALWAYS give a result greater than 11?

Mathematics
1 answer:
masha68 [24]3 years ago
4 0
AS i solve the work i quickly realized that 

<span>A.5 × a number less than 1 is incorrect do to the form of the placement and how it's written and that number is not Always greater than 1 


</span><span>B.4/9+ a fraction less than 12 is incorrect Cause that statement that would be there is true that it is less than were looking for greater then.

C. is correct this would be your answer. Why?

Reasoning:
1. The statmen placed on this one is true 1 & 3/4 is actually greater then 3/4 when if you just left that 1 & 3/4 with just a one it would still be greater
</span>
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Korolek [52]

Answer:

b is the answer trust me i know

Step-by-step explanation:

6 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
3 years ago
Frank and Jack are playing a number game.
Sveta_85 [38]
3, 7×3=21+5=26, there is your answer
6 0
3 years ago
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Answer:

6 hours

Step-by-step explanation:

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6 0
2 years ago
Please help with this question with steps I'll give brainliest!<br><br> Thanks
harina [27]

Answer:

∠ 1,3,5,7 = 32°

∠2,4,6,8,= 148°

Step-by-step explanation:

From the figure attached,

AB and CD are two parallel lines and another transverse line is intersecting these line at two distinct points.

Since, m∠1 = 32°,

∠1 and ∠4 are supplementary angles [Linear pair of angles]

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32° + m∠4 = 180°

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therefore,

m∠1,3,5,7 = 32°

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6 0
3 years ago
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