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V125BC [204]
3 years ago
6

12x^+2x^2=2y^2+28y-6

Mathematics
1 answer:
Ket [755]3 years ago
5 0

Hello,

There is no X intercept but there is a Y

Y intercept =  (0,-7 + 2 square root of 13),(0,-7,- 2 square root 13)

Center (-7,0)

Vertices: (−7+√x2+52,0),(−7−√x2+52,0)

(-7+x2+52,0),(-7-x2+52,0)

Foci: (−

42−√42(x2+52) 6 ,0),(−

42+√42(x2+52)

6

,0)

(-42-42(x2+52)6,0),(-42+42(x2+52)6,0)

I honestly dont know what your trying to solve so im guessing thats what you wanted...

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Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 6) and (x₂, y₂ ) = (8, 4)

m = \frac{4-6}{8-3} = - \frac{2}{5}, hence

y = - \frac{2}{5} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, 4), then

4 = - \frac{16}{5} + c ⇒ c = 4 + \frac{16}{5} = \frac{36}{5}

y = - \frac{2}{5} x + \frac{36}{5} ← equation of line

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