All categories

3 years ago

If 20 students have only airpods,

Mathematics

1 answer:

Anika [276]3 years ago

8 0

Answer:

There should be 20 students that have both Beats and AirPods.

Step-by-step explanation:

There are 50 students in total.

20 students have only AirPods and 30 students have Beats. Out of the 30 who own Beats, there are 10 students that have ONLY Beats.

30 - 10 = 20.

It's a tricky question, but this is the correct answer!

<em>Hope This Helps!</em>

You might be interested in

Rahul has a farm he wishes to fence. The farm is the pentagon ABCDE, shown

Daniel [21]

The diagram of the pentagon is missing, so i have attached it.

Answer:

|AE| = 130 m

|DE| = 150 m

Perimeter of pentagon = 720 m

Step-by-step explanation:

From the diagram, we can find AE from pythagoras theorem;

|AE| = √(|AA'|² + 50²)

Where AA' is the length from A to the perpendicular angle.

Now, AB = 150, and A'B is parallel to 30 m. Thus, A'B = 30

AA' = AB - A'B = 150 - 30

AA' = 120

Thus;

|AE| = √(120² + 50²)

|AE| = √(14400 + 2500)

|AE| = √16900

|AE| = 130

Similarly,

|DE| = √(|DD'|² + |ED'|²)

ED' = BC - 50

ED' = 140 - 50

ED' = 90

Also, DD' is parallel to AA' and is = 120

Thus;

|DE| = √(120² + 90²)

|DE| = √22500

|DE| = 150

Perimeter of pentagon = 150 + 130 + 150 + 150 + 140 = 720

4 0

3 years ago

Pls help asap!:) tysm<3

ale4655 [162]

m⁰ / u^(-3) = u³

= (-2)³

= -8

7 0

3 years ago

If you draw a card with a value of four or less from a standard deck of cards I will pay you $43 if not you pay me $10. Step 1.

Vera_Pavlovna [14]

The expected value of the game is its average earnings

The expected value of a round is $2.23
The expected value when the game is played 755 times is $1683.65

<h3>How to determine the expected value of a round</h3>

There are 12 cards with a value of 4 or less.

So, the probability of selecting a card with a value of 4 or less is:

$P(x \le 4) = \frac{12}{52}$

The probability of selecting a card with a value more than 4 is the complement of the above probability.

So, we have:

$P(x > 4) = 1 - \frac{12}{52}$

$P(x > 4) = \frac{40}{52}$

The expected value is then calculated as:

$E(x) = \frac{12}{52} * 43 - \frac{40}{52} * 10$

Evaluate

$E(x) = \frac{12* 43 - 40 * 10}{52}$

$E(x) = \frac{116}{52}$

Simplify

$E(x) = 2.23$

Hence, the expected value of a round is $2.23

<h3>The expected value when the game is played 755 times</h3>

In (a), we have:

$E(x) = 2.23$

In probability, we have:

$E(nx) = n * E(x)$

So, we have:

$E(755x) = 755 * 2.23$

$E(755x) = 1683.65$

Hence, the expected value when the game is played 755 times is $1683.65

Read more about expected values at:

brainly.com/question/15858152

6 0

3 years ago

two urns contain white balls and yellow balls the first urn contains 7 white balls and 7 yellow balls and the second urn contain

faltersainse [42]

<u>Answer:</u>

The correct answer option is b) $\frac{1}{6}$ .

<u>Step-by-step explanation:</u>

We are given that the first urn contains 7 white balls and 7 yellow balls and the second urn contains 3 white balls and 6 yellow balls. We are to find the probability that both balls drawn are white.

This means that the first must be white and the second ball must also be white.

P (w, w) = $\frac{7}{14}$ × $\frac{3}{9}$ = $\frac{1}{6}$

Therefore, the probability that both the balls drawn are white is 1/6.

5 0

4 years ago

WILL MARK THE BRAINIEST!!! LOTS OF POINTS!! HELP NOW

ElenaW [278]

cos (arctan (1))=

arctan (1) = 45 take it to the third quadrant = add 180 = 225

cos (225) = -1 / sqrt(2)

never leave a sqrt in the denominator

= -1 /sqrt(2) * sqrt(2)/sqrt(2)

= -sqrt(2)/2

sin (arccos (1/2)

arccos (1/2) = 60 take it to the 4th quadrant -60 degrees

sin (-60)

- sin 60

- sqrt(3)/2

3 0

3 years ago