The resulting matrix of the row operation is given as follows:
![R = \left[\begin{array}{ccc}7&4.5&-6\\-6&-3&12\end{array}\right]](https://tex.z-dn.net/?f=R%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%264.5%26-6%5C%5C-6%26-3%2612%5Cend%7Barray%7D%5Cright%5D)
<h3>How to find the resulting matrix?</h3>
We apply the row operation on the original matrix, given as follows:
![A = \left[\begin{array}{ccc}4&3&0\\-6&-3&12\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%263%260%5C%5C-6%26-3%2612%5Cend%7Barray%7D%5Cright%5D)
The operation is given by:
That is, applying to each element, we have that:
Hence the resulting matrix is:
More can be learned about matrix operations at brainly.com/question/1821869
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The first one is multiplying x^4 by itself 4 times and the second one is multiplying x^4 by 4 3 times
Answer:
It's +2
Step-by-step explanation:
As the positive occurs on the right side of the negatives in the number line so if we keep extending on the right side so we get +2
A): 2013 = 149.32
Find difference of: 194.31
2014 = 194<u>.31</u> <u>149.32</u>
= <u>44.99</u>
<u>2015</u> Total Will Be:
B):
149.32 + 25 = 174.32
(2013)
<h3> 174.32 + 44.99 = 219.31</h3>
(B) (A)
