Factorise 3(2x + 3y)^2 - 8x - 12y
First, we FOIL it.
FOIL: First, Outside, Inside, and Last
(2x + 3y)(2x + 3y)
First: 2x*2x = 4x^2
Outside: 2x*3y = 6xy
Inside: 3y*2x = 6xy
Last: 3y*3y = 9y^2
Before, we move on, we have to combine any like terms.
6xy + 6xy = 12xy
Then, when we've finished FOILing it, we place a pair of parentheses around these.
3 (9y^2 + 4x^2 + 12xy) -8x - 12y
Now, we can distribute the 3.
3 * 9y^2 = 27y^2
3 * 4x^2 = 12x^2
3 * 12xy = 36xy
Lastly, we combine any like terms if there are any.
Expression: 27y^2 + 12^2 + 36xy - 8x - 12y
None of these all have a greatest common factor for the whole set.
So, therefore, the factorised form of 3(2x + 3y)^2 - 8x - 12y is:
27y^2 + 12x^2 + 36xy - 8x - 12y
To do this, simply add the 2 functions-as it says:
(2x+1) + (-3x+4)
2x+1-3x-4
-x-3
Your answer is -x-3
It would be the 2nd one down and 3rd one up is the correct answer just look a little closer and you will see what i mean there ages are and and they have a 3o sec head start and they ran 60 yards in 30 sec.
Answer:
1 11/80
Step-by-step explanation:
1/5 + (3/4 × 1 1/4)
1/5 + (3/4 × 5/4)
1/5 + (15/16)
16/80 + 75/80
91/80
1 11/80