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alexgriva [62]
2 years ago
7

Could anyone help me with this? Thanks

Mathematics
1 answer:
NeTakaya2 years ago
7 0

Answer:

M: (2,-2)

N: (1,2)

O: (2,-4)

P: (5, -2)

Step-by-step explanation:

What you would do is find out where the two lines intercross. The 2 right quadrants are positive. The two left are negative. Count the lines and figure out the ordered pair. X is left and right, y is up and down. For example, if you were given a ordered pair, (4,-2) you would go up four, and left 2.

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You are the administrator of an annual essay contest scholarship fund. This year a $84,000 college scholarship is being divided
shutvik [7]

The winner got $70,000 and the runner up got $14,000

Let the winner be represented by x and runner up by y

Data given;

  • Amount to be shared = $84000
  • x = 5y

This is a simple case of ratio i.e 1 : 5

<h3>Equation</h3>

x = 5y\\84000 = 5y + y\\84000 = 6y\\y = 14000\\

The runner up received $14000. let's use this data to find how much the winner got.

x = 5y \\x = 5 * 14000\\x = 70000

From the calculations above, the winner got $70,000 and the runner up got $14,000.

Learn more about ratios here;

brainly.com/question/1781657

3 0
2 years ago
Which of the following is a PRIME number?
rosijanka [135]
The answer is 17 because all the others can be Times by more than one and itself
6 0
3 years ago
Read 2 more answers
What’s 2(2a+ 3b - 4) if a=2 and b=3
Aleksandr [31]

Answer:

2 ( 2a + 3b - 4)

Putting the value of a= 2 and b = 3 in the equation

2( 2(2) + 3(3) -4)

2 (4 + 9 -4)

2( 4 -4 + 9)

2 (0 + 9)

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2 × 9

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3 years ago
Line parallel to y-1=4(x+3) and passes through (4,32)
Lady_Fox [76]

Answer:

y - 32 = 4(x - 4)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 1 = 4(x + 3) ← is in point- slope form

with slope m = 4

Parallel lines have equal slopes.

Using m = 4 and (a, b) = (4, 32), then

y - 32 = 4(x - 4) ← equation of parallel line

6 0
3 years ago
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
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