Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Its B bro becauseiys a negative so you would get rid of the symbol then flip the negative
(x-9) (x+2)=x²+2x-9x-18=x²-7x-18
The difference between 1/2 and 1/6 is 2/6. So to write an expression we could do x divided by 2/6=2/3. So instead of a division expression, we could make that into a multiplication problem 2/6 times 2/3=x. 2/6 times 2/3= 4/18 so your answer is 4/18 or 2/9
