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tino4ka555 [31]

3 years ago

12

Can a line be parallel to a segemnt?

1 answer:

zmey [24]3 years ago

6 0

Y<span>ou </span>can<span> describe </span>lines<span>, rays, and </span>line segments<span> by the way they meet or cross each other. Words </span>Parallel lines<span> are always the same distance apart. They do not meet. Words </span>Lines<span> that meet or cross each other are called intersecting </span>lines<span>. Hope this helps.</span>

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Gnesinka [82]

Answer:

13

Step-by-step explanation:

We know that a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2 + 12^2 = c^2

25+144 = c^2

169 = c^2

Taking the square root of each side

sqrt(169) = sqrt(c^2)

13 =c

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2 years ago

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Y_Kistochka [10]

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these are only the answers for the first two problems

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3 years ago

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Someone please help ASAP. 15 points and I’ll mark brainliest.

lyudmila [28]

Answer:

first is linear second is quadratic and third looks like linear

Step-by-step explanation:

1. its a continuous straight line, linear

2. parabola shaped, quadratic

3. again a straight line, so linear

3 0

3 years ago

While cooking soup, Marry used 5 7 of a shaker of salt and 3 5 of a shaker of pepper. How much more salt was used than pepper?

Ymorist [56]

There was 22 more shakers of salt than pepper

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3 years ago

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There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level

aliya0001 [1]

Answer:

$d = 787.81cm^3$

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

$r=4cm$ --- radius

$h = 13cm$ --- height

The volume is calculated as:

$Volume = \frac{1}{3} \pi r^2h$

So, we have:

$V_1 = \frac{1}{3} \pi * 4^2 * 13$

$V_1 = \frac{208}{3} \pi$

The snow cone in a cup has the following dimension

Shape: Cylinder

$r=8cm$ --- radius

$h = 5cm$ --- height

The volume is calculated as:

$Volume = \pi r^2h$

So, we have:

$V_2 = \pi *8^2 * 5$

$V_2 = \pi *320$

$V_2 = 320\pi$

The difference (d) in the amount they hold is:

$d = V_2 - V_1$

$d = 320\pi - \frac{208\pi}{3}$

Take LCM

$d = \frac{3*320\pi -208\pi}{3}$

$d = \frac{960\pi -208\pi}{3}$

$d = \frac{752\pi}{3}$

Take $\pi = 22/7$

$d = \frac{752}{3} * \frac{22}{7}$

$d = \frac{752 * 22}{3*7}$

$d = \frac{16544}{21}$

$d = 787.81cm^3$

4 0

3 years ago