The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.
Answer:
Results:
0.1432
0.0045
0.0905
0.0483
Step-by-step explanation:
Step a:
P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432
Step b:
P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045
Step c:
P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905
Step d:
P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483
As well we get the probability by subtracting a, b and c:
P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482
Answer:
20.39
Step-by-step explanation:
35.99 – 15.6 = 20.39
The average is (0.76+0.88) / 2 = 1.64 / 2 = 0.82
