The solution to the problem is as follows:
let y = asinx + bcosx
<span>
dy/dx = acosx - bsinx </span>
<span>
= 0 for max/min </span>
<span>
bsinx = acosx </span>
<span>
sinx/cosx = a/b </span>
<span>
tanx = a/b </span>
<span>
then the hypotenuse of the corresponding right-angled triangle is √(a^2 + b^2) </span>
<span>the max/min of y occurs when tanx = a/b </span>
<span>
then sinx = a/√(a^2 + b^2) and cosx = b/√(a^2 + b^2) </span>
<span>
y = a( a/√(a^2 + b^2)) + b( b/√(a^2 + b^2)) </span>
<span>
= (a^2 + b^2)/√(a^2 + b^2) </span>
<span>
= √(a^2 + b^2)</span>
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Answer:
4 1/9
Step-by-step explanation:
Add all of them together. you get 37. Then divide them by how many numbers. You get 4.111 repeating. I then just turned that into a fraction and got 4 1/9
Y-2 = m (x-6), where m = (2-4)/(6-2) = -2/4 = -1/2
y-2 = 1/2 (x-6)
Answer: x<6
Step-by-step explanation:
12.0 is the answer I think
