Question

Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). What is the y-value of P'?

Answer 1

Answer:

The y-value of P' is -10.

Step-by-step explanation:

It was given that; triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2).

The translation rule is

$(x,y)\to (x-2,y-16)$

To find the image of P, which is P', we have to substitute the coordinates of P(-2,6) to obtain;

$P(-2,6)\to P'(-2-2,6-16)$

$P(-2,6)\to P'(-4,-10)$

Hence the y-value of P' is -10.