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katrin [286]
3 years ago
13

Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha

t is the y-value of P'?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

The y-value of P' is -10.

Step-by-step explanation:

It was given that; triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2).

The translation rule is

(x,y)\to (x-2,y-16)

To find the image of P, which is P', we have to substitute the coordinates of P(-2,6) to obtain;

P(-2,6)\to P'(-2-2,6-16)

P(-2,6)\to P'(-4,-10)

Hence the y-value of P' is -10.

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