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3 years ago

How to solve area for math

Mathematics

1 answer:

Airida [17]3 years ago

5 0

For a triangle it’s height times width.

For a square all you need is one sides length sense all the sides are the same. Then multiply it by itself!

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The GCF of 28 and 64 is 2 4 7 8

konstantin123 [22]

The greatest comment factor of 28 and 64 is 4.

The factors of 28 are 28, 14, 7, 4, 2, 1.
The factors of 64 are 64, 32, 16, 8, 4, 2, 1.

The common factors of 28 and 64 are 4, 2.

the greatest one of the two factors is 4.

8 0

3 years ago

Read 2 more answers

Someone please help me now!!!

elena55 [62]

2. 80%
3. all
4. .70
I hope this helps

5 0

4 years ago

PLS HELP ASAP ON THESE PROBLEMS I NEED THIS RN

julsineya [31]

1). 140 tomatoes
7/5= 1.4
1.4(100)=140
2). 41 people
58/1.4= 41.4

6 0

3 years ago

Can anyone do 4,5 and 6 for me plz

cricket20 [7]

For question 4, $sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.$

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

$sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.$

Step 2:

Using the above formula, we solve the following values

$sinA = \frac{oppositeside}{hypotenuse}$ $=\frac{a}{c}.$

$cosA = \frac{adjacentside}{hypotenuse}$ $= \frac{b}{c}.$

$tanB= \frac{opposite side}{adjacent side}$ $= \frac{b}{a}.$

$sinJ = \frac{oppositeside}{hypotenuse}$ $= \frac{j}{l}.$

$cosK = \frac{adjacentside}{hypotenuse}$ $= \frac{j}{l}.$

$tanK= \frac{opposite side}{adjacent side}$ $= \frac{k}{j}.$

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

$sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.$

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

$tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277$

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0

3 years ago

Which expression is equivalent to -6(3x-2/3) -2x+9 -3x-6(2/3) -18x+12 -18x+4

finlep [7]

Answer:

option d is correct answer

Step-by-step explanation:

-18x+12

6 0

3 years ago