Puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5
B
given f(x) in factored form, equate to zero for x-intercepts
(x - 8)(x - 4) = 0, hence
x = 4, x = 8 ← x- intercepts
The vertex lies on the axis of symmetry which is situated at the midpoint of the x- intercepts
x- coordinate of vertex = 
= 6
f(6) = (6 - 8 )(6 - 4 ) = -2 × 2 = - 4 ← y-coordinate
vertex = (6, - 4 ) → B
Answer:
$54.51
Step-by-step explanation:
an easier way to do this is simply by multiplying 47.40x115%, which is 54.51.
another way to do this is by multiplying 47.40x15%, which is 7.11, then you'll have to added to 47.4, which gives you the same answer of 54.51
Answer:
Here is the full proof:
AC bisects ∠BCD Given
∠CAB ≅ ∠CAD Definition of angle bisector
DC ⊥ AD Given
∠ADC = 90° Definition of perpendicular lines
BC ⊥ AB Given
∠ABC = 90° Definition of perpendicular lines
∠ADC ≅ ∠ABC Right angles are congruent
AC = AC Reflexive property
ΔCAB ≅ ΔCAD SAA
BC = DC CPCTC
Answer:
120 deg
Step-by-step explanation:
There is an angle symbol in the equilateral triangle and another symbol in half of the vertex angle. Those two angles are congruent.
The measure of the vertex angle is 2 * 60 deg = 120 deg
Answer: 120 deg
