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2 years ago

6

one afternoon, kassim's sandwhich shop sells 15 sandwiches in 45 minutes. if the shop counties to sell sandwiches at the same ra

te, about how many sandwiches will the shop sell in 3 hours.

1 answer:

Flauer [41]2 years ago

4 0

The answer is 60 sandwiches

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to arrive at 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution. How many liters of eac

CaHeK987 [17]

Answer:

<u>800 liters</u> of 90% saline solution and <u>1200 liters</u> of 40% saline solution should be used.

Step-by-step explanation:

Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

<u><em>Let the liters of 90% saline solution mix be </em></u> $x.$ <u><em /></u>

<u><em>And let the liters of 40% saline solution mix be</em></u> $y.$

So, the total number of liters:

$x+y=2000.$

$y=2000-x\ \ \ ....(1)$

Now, the total percentage of saline solution:

$90\%\ of\ x+40\%\ of\ y=60\%\ of\ 2000$

$\frac{90}{100}\times x+\frac{40}{100}\times y=\frac{60}{100}\times 2000$

$0.9x+0.4y=1200$

Substituting the value of $y$ from equation (1) we get:

$0.9x+0.4(2000-x)=1200$

$0.9x+800-0.4x=1200$

$0.5x+800=1200$

Subtracting both sides by 800 we get:

$0.5x=400$

Dividing both sides by 0.5 we get:

$x=800.$

<u>The liters of 90% saline solution mix = 800.</u>

Now, substituting the value of $x$ in equation (1) to get the liters of 40% saline solution:

$y=2000-x$

$y=2000-800$

$y=1200.$

<u>Thus, the liters of 40% saline solution = 1200.</u>

Therefore, 800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

8 0

3 years ago

Dont guess!<br> I will mark brainliest if its correct!<br> Also no links!

brilliants [131]

Answer:

I know you said no guessing, but I'm assuming it's the first one, F.

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2 years ago

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HELP I DONT UNDER STAND INTERGERS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

MAXImum [283]

Answer:An integer (from the Latin integer meaning "whole") is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 512, and √2 are not. ... ℤ is a subset of the set of all rational numbers ℚ, which in turn is a subset of the real numbers ℝ.

Step-by-step explanation:

An integer (from the Latin integer meaning "whole") is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 512, and √2 are not. ... ℤ is a subset of the set of all rational numbers ℚ, which in turn is a subset of the real numbers ℝ.

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3 years ago

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Ples help smart redstoners

morpeh [17]

44because when you do the math it came out to that

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2 years ago

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How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago