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erik [133]
3 years ago
10

What is 120/1,000 simplified??????????????????????????????????????????????????????????/

Mathematics
2 answers:
Nikolay [14]3 years ago
5 0
0.12 is your answer!
dedylja [7]3 years ago
5 0
The answer is 3/25.

Hope this helps!
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What is 58.65 with a 15% tip?
11111nata11111 [884]
X/58.65 = 15/100

(58.65*15)/100 = tip
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A drama club earns $1040 from a production. It sells a total of 64 adult tickets and 132 student tickets. An adult ticket costs
STatiana [176]
16x + 33y = 260, I think this is correct. Hope this helps!:)
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3 years ago
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The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 48 and the common rati
Aleks [24]

Answer:

The sigma notation would look like this:

∞

Σ       48(1/4)^i-1

i = 1

Step-by-step explanation:

I can't seem to find a good way to make it more connected so I'll just have to tell you. The ∞ is above the ∑, while the i = 1 is under it. That is all one thing. The rest is followed as normal, and it is all next to the ∑

7 0
3 years ago
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What is the solution of
kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

\sqrt{2x+4}-\sqrt{x}=2

Isolating √(2x+4): Addind √x both sides of the equation:

\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}

Squaring both sides of the equation:

(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}

Simplifying on the left side, and applying on the right side the formula:

(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}

2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}

Squaring both sides of the equation:

(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

x^{2}-16x=16x-16x\\ x^{2}-16x=0

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2

x=0 is a solution


2) x=16

\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2

x=16 is a solution


Then the solutions are x=0 and x=16


5 0
3 years ago
Simplify 6(1/4+5/2)-2
zysi [14]
6(0.25+2.5)-2
6(2.75)-2
16.5-2
=14.5
7 0
4 years ago
Read 2 more answers
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