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Sav [38]
3 years ago
7

3x + x + x + x − 3 − 2 = 7 + x + x In the equation above, what is the value of x?

Mathematics
1 answer:
algol133 years ago
7 0

Answer:

x=3

Step-by-step explanation:

3x + x + x + x − 3 − 2 = 7 + x + x

Combine like terms

6x -5 = 7+2x

Subtract 2x from each side

6x-2x -5 = 7+2x-2x

4x-5 =7

Add 5 to each side

4x-5+5 = 7+5

4x =12

Divide by 4

4x/4 = 12/4

x = 3

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3 years ago
write the given equation into vertex form and sketch the graph. Determine the domain and range f(x)=3x^2-6+2 plss help
LuckyWell [14K]

Answer: the range would thus be [-3, 1/3].)

Step-by-step explanation:

1. To sketch the function f(x) = (2/3)x - 3, we first need to find two points that we can later join to sketch the line, for example the x- and y-intercepts.

a) The x-intercept occurs when f(x) = 0, so if f(x) = 0, then:

f(x) = (2/3)x - 3

0 = (2/3)x - 3

3 = (2/3)x (Add three to both sides)

3*(3/2) = x (Multiply both sides by 3/2)

9/2 = x

We have now found the x-intercept at (9/2, 0)

b) The y-intercept occurs when x = 0, so:

f(x) = (2/3)x - 3

f(0) = (2/3)*0 - 3

f(0) = -3

Now we know that the y-intercept is at (0, -3)

c) All that's left is to sketch the graph axes and label them, plot the two points, join them together using a ruler and label their coordinates.

2. The Domain is the range of x-values for which the function exists, and the Range is the range of y-values for which the function exists.

Since there haven't been any constraints specified, we can say that both the Domain and Range are (-∞, ∞), since the graph continues forever both along the x- and y-axis.

(Note that this isn't always the case and would change if, for example, the question stipulated that there was a domain of [0, 5] and you had to find the range. Then, you would calculate the value of y at each end of the domain (if x = 0, y = -3 and if x = 5, y = 1/3) - in my example, the range would thus be [-3, 1/3].)

4 0
3 years ago
If f(x)=-3x+1 then f^-1(x)=
enyata [817]

Answer:

f^-1 (x) = (1 - x)/3.

Step-by-step explanation:

f(x) = -3x + 1

3x = 1 - f(x)

x = (1 - f(x)) / 3

So f^-1 x = (1 - x)/3.

6 0
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