An arrow is launched upward with a velocity of 192 feet per second from the top of a 95-foot stage. What is the maximum height a
ttained by the arrow?
1 answer:
9514 1404 393
Answer:
671 feet
Step-by-step explanation:
There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².
v² = 2ad
d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft
This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...
max height = 95 ft + 576 ft = 671 ft
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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...
h(t) = -16t^2 +192t +95
The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:
t = -(192)/(2(-16)) = 6
Then the maximum height is ...
h(6) = -16·6^2 +192·6 +95 = 671
The maximum height is 671 feet.
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<em>Additional comment</em>
For the standard-form quadratic ...
y = ax^2 +bx +c
The axis of symmetry is ...
x = -b/(2a)
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I'm not sure about the first question.
Did you post the question correctly?
Did you post the question correctly?
Using scientific notation, it is found that:
67 ns = s
A number in scientific notation is given by:
With the base being .
In this problem, the amount is of 67 ns.
Each ns has seconds, hence:
We want the base between 1 and 10(exclusive), hence, we move the decimal digit one digit to the left and add one to the exponent, and the representation is:
67 ns = s
You can learn more about scientific notation at brainly.com/question/16394306
Answer:
Step-by-step explanation:
As you can observe in the image attached, the line that best fits passes through point B and C. That means we can use those point to find the slope of such line.
Where and
So, the slope of the line that best fits is -11, approximately.
Now, we use the point-slope formula to find the equation.
Therefore, the line that best fits is approximately.
Remember, when we estimate a line for some data on a scatterplot, we are calculating an approximation, that's why we also said "approximately", because the line is an approximation where the majority of point meet.
