Answer: (1+2a)^2 or (1+2a)(1+2a)
Step-by-step explanation:
Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
10/12= $.83 per inch
20/18= $1.11 per inch
Answer:
Yes, one of a rhombus's properties is that the diagonals bisect vertex angles.
9514 1404 393
Answer:
3x -4y = -9
Step-by-step explanation:
Multiply by 4 to clear the fraction.
4(y -6) = 3(x -5)
Subtract the left-side term to get variables on the same side, with a positive x-coefficient.
0 = 3(x -5) -4(y -6)
Eliminate parentheses and collect terms.
0 = 3x -15 -4y +24
0 = 3x -4y +9
Subtract 9 and swap sides to get standard form.
3x -4y = -9
_____
Standard form is ...
ax +by = c
where a ≥ 0, and a, b, c are mutually prime integers. If a=0, then b > 0.
__
The attached graph shows the equations give the same line. The original line is shown dotted so that you can see they overlap.