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Jobisdone [24]
3 years ago
12

Orthographic projection and isometric projection are two ways to show three-dimensional objects in a two-dimensional space, such

as on a piece of paper or a computer screen. Each method gives a different perspective. Do some research and then compare and contrast the two methods for displaying three-dimensional shapes. Then try your hand at creating both types of projections for a simple geometric shape using paper, pencil, and a ruler. In your opinion, what are the pros and cons of each projection? What are the limitations? In which circumstances, environments, or occupations is one type of projection likely preferred over the other? Describe any special tools that might be needed to create the projection. Which projection is easiest for you to interpret visually? Why?
Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

Orthographic Projection is used for making the projects but Isometric Projection is used to have better understanding of the object.

Orthographic drawings are typically two dimensional views of an object. For instance, if you were designing a table, you would draw a top view, side view and a bottom view. Should these three views not fully explain the design of the table other views would need to be drawn. When drawing an perspective view in an orthographic manner, you would utilize a 45 degree triangle for the lines that extend back or forward from the vertical lines. This type of perspective is not a true perspective because you can measure the true length of all the details shown. An isometric drawing is meant to depict a 3D image of an object in what appears to be a perspective view. However, similar to an orthographic perspective, all of the lines in an isometric drawing can be measured to their true length. What makes it different from an orthographic perspective is that its angled lines are drawn at 30 or 60 degrees or divisions of them. Drawing this by hand you would use a 30/60/90 triangle.

In either case, both types of perspectives can be accurately measured with a ruler in order to know the objects measurements.

Step-by-step explanation:

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Answer:

g(-3)=-2

Step-by-step explanation:

<u>Substitute g(-3) into the function:</u>

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<u>Add:</u>

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7 0
3 years ago
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The perimeter of a rectangular construction site is 124 meters. The width is eight meters more than 5 times the length. Find the
tresset_1 [31]

Answer:

The perimeter of a rectangle is the sum of both lengths and both widths, which is equal to 54 meters. Let's call Length L and Width W.

The question is saying this: L = 3 meters + 3(W). We have 2 variables, which means we need at least 2 equations to solve. So far we have one, our second equation is from the perimeter.

2 lengths + 2 Widths = 54. Now, it's just a plug and chug.

2(3 + 3W) + 2W = 54.

6 + 6W + 2W = 54

8W = 48

W=6

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The Width is 6 meters, and the Length is 21 meters.

7 0
3 years ago
My Notes A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 f
Sergio [31]

Answer:

6.667 ft/s

Step-by-step explanation:

Given

Height of street light = 15ft

Height of man = 6ft

Speed away from pole = 4ft/s

Let x represents the distance between the man and the pole, and Let y represents the distance between the tip of the man's shadow to the pole.

This forms a similar triangle (see attachment below).

From similar triangles, we have

(y - x)/6 = y/15 ----- Solve equation

15(y - x) = 6 * y

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y = 5x/3 ---- differentiate with respect to time, t

dy/dt = 5/3 dx/dt

dx/dt represents rate of change of distance per time = 4ft/s

while dy/dt represents rate of movement of his shadow tips

dy/dt = 5/3 * 4

dy/dt = 20/3 = 6.667 ft/s

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stepan [7]
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Answer:

120 in

Step-by-step explanation:

(5 in * 12 in)/2 = 30 in

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I hope that helps :D

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