we have been asked to find the sum of the series
As we know that a geometric series has a constant ratio "r" and it is defined as
The first term of the series is 
Geometric series sum formula is
Plugin the values we get
On simplification we get
Hence the sum of the given series is 
Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
Therefore, the coefficients of the expansion are given by:
1, 6, 15, 20, 15, 6, 1
Answer:
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
(c+8)(c-8)
3(2y+5)(2y-5)
There are no like terms so it's still ab^2-b
Answer:
c=√a²+b²
Step-by-step explanation:
You can use this equation to solve it.
857 x 132= 113,124
work is showed in the image
