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Sergeu [11.5K]
3 years ago
5

Kevin had a total of $320 to spend while shopping. He had spent $156 on video games. He wants to buy caps that are on sale for $

15 each including tax. Find the maximum number of caps that he can buy with the remaining money.
Mathematics
1 answer:
zloy xaker [14]3 years ago
8 0

Maximum number of caps that Kevin can buy is 10.

Solution:

Total money for shopping = $320

Amount spent for video game = $156

Remaining amount that Kevin had = $320 – $156

                                                         = $164

Cost of each cap including tax = $15

$\text{Number of caps can buy }=\frac{\text { Remaining amount that Kevin had }}{\text { cost of each cap }}$

                                       $=\frac{164}{15}

                                      $=10\frac{14}{15}

Maximum number of caps that Kevin can buy is 10.

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Answer:

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Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

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where, \hat p = sample proportion of people who disagree with the statement = \frac{1812}{2625} = 0.69

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<u>So, 99% confidence interval for the population proportion, p is ;</u>

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5% level

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P(-2.58 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.58) = 0.99

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P( \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

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= [ 0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } , 0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } ]

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Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

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