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3 years ago

Answer the attachment please And subscribe to Offxcial PrxmiiseX=8 and y=3

Mathematics

1 answer:

-Dominant- [34]3 years ago

3 0

Answer:

Step-by-step explanation:

8^2+3^2=64+9=73

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Jenny has some tiles in a bag. The tiles are of three different colors: purple, pink, and orange. Jenny randomly pulls a tile ou

umka21 [38]

Number of experimental pinks drawn / number of experimental picks...

4/(4+24+22)

4/50

2/25 or (8%)

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4 years ago

The interest on $2,000 for 2 years is $320. What is the simple interest rate?

umka2103 [35]

R = 8%/year

Equation:
r = (1/t)(A/P - 1)
Calculation:
Solving our equation:
r = (1/2)((2320/2000) - 1) = 0.08
r = 0.08

Converting r decimal to R a percentage
R = 0.08 * 100 = 8%/year

The interest rate required to get a total amount, principal plus interest, of $2,320.00 from simple interest on a principal of $2,000.00 over 2 years is 8% per year.

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3 years ago

PLSS HELP WILL MARK BRAINLIEST <br><br> I NEED THIS WRITTEN ON PAPER

Greeley [361]

What points are A and C? I can see that point B is (-5,3) and point D is (2,1) but what is point A and point C?

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3 years ago

Read 2 more answers

Calculate the limit of the function with L'Hospital rule

mr_godi [17]

Answer:

L=24

Step-by-step explanation:

L'Hopital's Rule for Evaluating Limits:

Rule is that if $\lim_{x \to a} \frac{f(x)}{g(x)}$ takes $\frac{0}{0}$ or $\frac{\infty}{\infty}$ form, then,

$\lim_{x \to a} \frac{f(x)}{g(x)}= \lim_{x \to a} \frac{f'(x)}{g'(x)}$

where $f'(x)=\frac{df(x)}{dx}$ and $g'(x)=\frac{dg(x)}{dx}$

Now coming to the problem,

$L= \lim_{x \to \frac{\pi}{6} } \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3} )}$

Here $f(x)=cot^{3}x-3cotx$ and $g(x)=cos(x+\frac{\pi}{3} )$

Substituting $x=\frac{\pi}{6}$ in f(x) and g(x),

$f(\frac{\pi}{6})=cot^{3}\frac{\pi}{6}-3cot\frac{\pi}{6}\\=3\sqrt{3}-3\sqrt{3}\\ =0$

$g(\frac{\pi}{6})=cos(\frac{\pi}{6}+\frac{\pi}{3})\\=cos\frac{\pi}{2}\\=0$

Since L takes the form $\frac{0}{0}$ , using l'hopital's rule

$L= \lim_{x \to \frac{\pi}{6}} \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3})}= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}x(-cosec^{2}x)-3(-cosec^{2}x)}{-sin(x+\frac{\pi}{3})}$

now substituting $x=\frac{\pi}{6}$ ,

$L= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}\frac{\pi}{6}(-cosec^{2}\frac{\pi}{6})-3(-cosec^{2}\frac{\pi}{6})}{-sin(\frac{\pi}{6}+\frac{\pi}{3})}\\=\frac{3*3^{2}(-2^{2})+3(2^{2})}{-1}\\=24$

6 0

3 years ago

Convert the follow statement into a conditional statement. All squares are rectangles

mihalych1998 [28]

The best and most correct answer among the choices provided by your question is the second choice.

The statement "All squares are rectangles" converted into a conditional statement is "If an object is a rectangle, then it is a square. "

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

6 0

4 years ago