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Lelu [443]
3 years ago
15

4. Ten less than the product of six and eight less than a number

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0

Answer: 38

Step-by-step explanation:

6 x 8 = 48

48 - 10 = 38

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a leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. At that rate, how many gallons of water will the
Arisa [49]
You can either scale down so you can get to 48 hours or just multiply from 20 to 48 and I'll explain both ways.
Scaling down:
You can find how many hours it takes to get to 1 gallon in the bucket by dividing
20÷5=4; It takes 4 hours to fill it up to one gallon.
You can now divide 48 by 4 to see how many gallons it'll take up to 48 hours.
48÷4=12
Quicker:
Divide 48 by 20;
48÷20=2.4
Now multiply since it filled it up to 5 gallons.
2.4×5=12
It'll fill 12 gallons in 48 hours.
Tell me if this helps!!
7 0
3 years ago
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I think it’s C
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3 0
2 years ago
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Are the equations – 2x = 10 and -5x = 25 equivalent? Explain
Dahasolnce [82]

Answer:NO

Step-by-step explanation:

7 0
3 years ago
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Choose the pair of events that is mutually exclusive.​
barxatty [35]

Answer:

even numbers greater than 50 and prime numbers greater than 50

Step-by-step explanation:

An event can be considered as mutually exclusive in probability and statistics when two sample propositions cannot be held as true by any means. Therefore, the pair that clearly illustrates a mutually exclusive event would be "even numbers greater than 50 and prime numbers greater than 50."

The only prime number that is even is 2, so even numbers over 50 would be divisible by 2, and then not prime.  

5 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
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