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Helga [31]
2 years ago
10

7. A coin is tossed and a day of the week is selected. What is the probability that you get tails and a day that begins with "S"

?
Mathematics
1 answer:
Mrrafil [7]2 years ago
6 0

Answer:

1/7

Step-by-step explanation:

Lets start with the probability of flipping tails, 1/2.

Then the probability of the day starting with the letter s, 2/7.

Calculate the final probability by multiplying the two together.

\frac{1}{2}*\frac{2}{7}=\frac{2}{14}

You can simplify 2/14 down to 1/7

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Use definition of the derivatives to find the derivative of each function with respect to x.
yanalaym [24]
Answer:
The slope is 5
Step-by-step explanation:
This equation is in slope intercept form
y = mx +b
where m is the slope and b is the y intercept
y = 5x+4
where 5 is the slope and 4 is the y intercept
6 0
3 years ago
The cost of renting a car is $29.00 a day plus $0.25 for every kilometre after the first 100km. What is the cost of renting the
ira [324]

Answer:

$461

Step-by-step explanation:

First, find the cost with the daily charge of $29.

Multiply 14 by 29, since the car was rented for 14 days:

14(29)

= 406

Find the cost with the distance traveled. Since there is only a charge after the first 100 km, subtract 100 from 320.

320 - 100

= 220

Find the charge by multiplying this by 0.25:

220(0.25)

= 55

Add this to the daily charge:

55 + 406

= 461

So, the cost will be $461

3 0
3 years ago
I’ll give brainlest please help!
boyakko [2]
The surface area is 158 inches.
4 0
3 years ago
What is the range of the function f(x) = sqrt x+3   – 7?
anyanavicka [17]

The values produced by the function

f(x)=\sqrt{x+3}-7

will not be any lower than -7, but may be that low when x=-3.

That is, the range is

... f(x) ≥ -7 . . . . matches the 1st selection

7 0
3 years ago
Read 2 more answers
Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)​
nikdorinn [45]

Answer:

I think that it should be

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

Step-by-step explanation:

Here,

we take , a - b = A,b-c = B , c - a= C

A+B+C = 0

we know that,

{a}^{3}  +  {b}^{3}  +  {c}^{3}   - 3abc = (a + b + c)(  {a}^{2}  +  {b}^{2}  +  {c}^{2}  - ab - bc - ca)

Here , A+B+C = 0

so,

A^3 +B^3 + C^3 = 3 ABC

now we put the values

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

I am done .

4 0
4 years ago
Read 2 more answers
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