Would it be C? im not too sure but thats my guess =)
9514 1404 393
Answer:
A. 54
Step-by-step explanation:
The two marked angles are "vertical angles," so are congruent.
125° = (2x +17)°
108 = 2x . . . . . . . . divide by °, subtract 17
54 = x . . . . . . . . . . divide by 2
Answer:
a. 79
Step-by-step explanation:
Use this theorem
Answer:
The ratio representing the tangent of ∠K is 40 : 9.
Step-by-step explanation:
Consider the right-angles triangle KLM below.
The angle M is 90°.
KM = perpendicular (<em>p</em>) = 40
ML = base (<em>b</em>) = 9
LK = hypotenuse (<em>h</em>) = 41
The tangent of an angle is the ratio of the perpendicular length to the length of the base.
Compute the tangent of ∠K as follows:
Thus, the ratio representing the tangent of ∠K is 40 : 9.
Answer:
y = 3x² – 9b + 3 and the parabola opens upwards since a = 3 > 0.
Step-by-step explanation:
The general equation of a parabola is:
y = ax² + bx + c
So we have to solve for a, b and c to get our equation with the 3 given points.
When x = 0 and y = 3 we have
3 = a(0)² + b(0) + c, this means c = 3
When x = 4 and y = 15
15 = a(4)² + b(4) + 3 we have
16a + 4b = 12 which is
4a + b = 3
When x = 5 and y = 33 we have
33 = a(5)² + b(5) + 3 we have
25a + 5b = 30 which gives
5a + b = 6.
We have two equations
4a + b = 3
5a + b = 6
Eliminating b we have
a = 3, substituting a = 3 in the first equation we have
4(3) + b = 3
12 + b = 3
b = –9
Our equation therefore is:
y = 3x² – 9b + 3 and the parabola opens upwards since a = 3 > 0.
